[FOM] Correction to problem on order types
Robert M. Solovay
solovay at Math.Berkeley.EDU
Sun Mar 6 01:05:37 EST 2005
Joe,
Can you elaborate what the error is? I got eleven as well. The
empty set; the one point set and then 3 times 3 where the possibilities
are open, closed, or "the long line" for each end.
--Bob Solovay
On Sat, 5 Mar 2005 JoeShipman at aol.com wrote:
> In the statement of the problem, I should require that every open interval (a,b) with a<b is isomophic to the real numbers, not rational numbers.
>
> That was the form I had originally come up with the problem, but then I got too clever. Dave Marker claims that changing "reals" to "rationals" allows more solutions than I had contemplated, and pointed out why my comtemplated proof for "rationals" fails.
>
> -- JS
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