FOM: epsilon terms and choice
Kanovei
kanovei at wmwap1.math.uni-wuppertal.de
Mon Sep 25 10:44:42 EDT 2000
> Date: Sun, 24 Sep 2000 23:59:52 +0100
> From: "V. Yu. Shavrukov" <vys1 at mcs.le.ac.uk>
> Still, to model epsilon terms with G, I seem to need
> Foundation: G chooses from all sets, whereas epsilon
> terms choose from possibly class-sized collections, so
> under Foundation you just restrict to elements of minimal
> rank and get sets. Is there a way to do it differently?
I don't know. The question can be interesting even for
well-defined theories without Regularity like IST.
> I seem to remember somebody commenting that
> epsilon terms are easily explained away in terms of
> less exotic things in a fairly general setup.
> The explaining away that depends on Foundation does
> not appear too general to me.
Here there is hardly anything to "explain":
indeed, both \epsilon-terms and
global choice do not exist in the ordinary mathematical
universe, hence, the mathematical side of the problem is
to verify if the apparently stronger assumption in fact follows
formally from the ther one. This can be just true or false,
without any foundational application.
> Mathias, in his recent paper
> (Bulletin London M.S., this year, number 5) tacitly
> equates "Bourbachisme" with ZC.
>
> I am not however sure that this should be interpreted
> as him saying that Z+epsilon is conservative over
> ZC, but this would be my natural reaction.
> Any comment?
To verify that ZFGC is conservative over ZFC they extend the
universe V of all sets by a generic global choice function
such that no new sets are added. A straightforward implementation
of this argument w.r.t. ZC does not work: to prove that no new
sets are added one has to apply Replacement, not only Separation,
in the ground universe. This is what I had in mind.
Perhaps, a modification, which Mathias is aware of, solves
the difficulty, or the conservativity of ZGC over ZC can be obtained
by a totally different argument.
V.Kanovei
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