FOM: rings vs. algebras
kanovei at wminf2.math.uni-wuppertal.de
Sun Mar 15 15:06:34 EST 1998
<Date: Sun, 15 Mar 1998 10:44:14 -0800
<From: Vaughan Pratt <pratt at cs.stanford.edu>
<every Boolean ring *is* a Boolean algebra
Let me stick on this claim.
As it is clear that
formally BR and BA are objects of different signature,
the only way I see to understand the claim is that there
is a definition of the signature of BR in terms of the
signature of BA, and a definition in the opposite
direction, which convert each BA in BR and vice versa,
and (most likely) give the identity in composition
Is there such ? Or the reasoning is driving at something
like *clones of hemidemisemifemtomorphism* ?
Please continue to comment.
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